Print alphabet pattern ‘d’¶
Print alphabet pattern ‘d’.
Expected output:
0123456
0 ****
1 * *
2 * *
3 * *
4 * *
5 * *
6 ****
result_str = ""
for row in range(0, 7):
for column in range(0, 7):
if (column == 1
or
(
(row == 0 or row == 6) and
(column > 1 and column < 5)
)
or
(column == 5 and row != 0 and row != 6)
):
result_str += "*"
else:
result_str += " "
result_str += "\n"
print(result_str)
Output:
****
* *
* *
* *
* *
* *
****